problem 22, page 245
22. What volume is occupied by 0.40 mol of
natural gas (CH4) at 200C and 760 torr?
PV = nRT
P = 760 torr and V can be in any L or mL, depending on units of R; so let’s choose R = 62.4 L torr/mol K
V = nRT/P
V = (.40 mol)(62.4 L torr/mol K)(293 K)/760 torr
(L)(mol)(torr)(K)
(mol)(K)(torr)
(.40)(62.4)(293)
760
= 9.6 L
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